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JEE Main 202118 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Evening Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2021 · 18 March · Evening Shift · Mathematics · Binomial Theorem

Let Cr n denote the binomial coefficient of x ^ r in the expansion...

Let CrnCr n denote the binomial coefficient of xr{x}^{r} in the expansion of (1+x)n( 1 + x{)}^{n}. If ∑k=010(22+3k)Ckn=α.310+β⋅210,α,β∈R\mathop{∑}_{k = 0}^{10}\left({2}^{2} + 3k\right) Ck n = \alpha . {3}^{10} + \beta \cdot {2}^{10}, \alpha, \beta \in R, then α+β\alpha + \beta is equal to ___ .

Correct answer

0

Step-by-step solution

Instead of CknCk n it must be Ck10Ck 10 i.e.

∑k=010(22+3k)Ck10=α⋅310+β⋅210\mathop{∑}_{k = 0}^{10}\left({2}^{2} + 3k\right) Ck 10 = \alpha \cdot {3}^{10} + \beta \cdot {2}^{10}

LHS=4∑k=010Ck10+3∑k=010k⋅10k⋅Ck−19LHS = 4\mathop{∑}_{k = 0}^{10} Ck 10 + 3\mathop{∑}_{k = 0}^{10}k \cdot \dfrac{10}{k} \cdot Ck - 1 9

=4.210+3.10.29= 4 . {2}^{10} + 3 . 10 . {2}^{9}

=19.210=α.310+β.210= 19 . {2}^{10} = \alpha . {3}^{10} + \beta . {2}^{10}

⇒α=0,β=19⇒α+β=19⇒ \alpha = 0, \beta = 19 ⇒ \alpha + \beta = 19

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