Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202118 Mar 2021Morning ShiftMathematicsBinomial TheoremActual

Let 1 + x + 2 x 2 20 = a 0 + a 1 x + a 2 x 2 + … + a 40 x 40 , then a 1 + a 3 + a 5 + … + a 37 is equal to

Options

  1. A2 20 2 20 - 21
  2. B2 19 2 20 - 21
  3. C2 19 2 20 + 21
  4. D2 20 2 20 + 21

Correct answer

B. 2 19 2 20 - 21

Step-by-step solution

Given 1 + x + 2 x 2 20 = a 0 + a 1 x + … + a 40 x 40 Put x = 1 we get, a 0 + a 1 + a 2 + … + a 40 = 4 20 Put x = - 1 we get, a 0 - a 1 + a 2 + … . + a 40 = 2 20 ⇒ a 1 + a 3 + … . + a 39 = 4 20 - 2 20 2 ⇒ a 1 + a 3 + … + a 37 = 2 39 - 2 19 - a 39 Here a 39 = 20 ! ( 2 ) 19 × 1 19 ! = 20 × 2 19 ⇒ a 1 + a 3 + … + a 37 = 2 19 2 20 - 1 - 20 = 2 19 2 20 - 21

Practice Binomial Theorem on Quantrex Academy →

More from Binomial Theorem

If 26 ( 2^3 3 12 2 + 2^5 5 12 4 + 2^7 7 12 6 + + 2¹³ 13 12 12 ) = 3¹³ - , then is equal to: 2026If (1 - x^3)¹⁰ = _ r=0 ¹⁰ a_r x^r (1-x)^ 30-2r , then 9a₉ a₁₀ is equal to __________. 2026If the coefficients of the middle terms in the binomial expansions of (1 + x)²⁶ and (1 - x)²⁸ , 0 , are equal, then the value of is: 2026The coefficient of x^2 in the expansion of (2x^2 + 1 x )¹⁰ , x 0 , is : 2026If the sum of the coefficients of x^7 and x¹⁴ in the expansion of ( 1 x^3 - x^4 )^n , x 0 , is zero, then the value of n is __________. 2026In the expansion of (9x- 1 3 x )¹⁸ , x>0 , if the term independent of x is (221)k , then k is equal to: 2026Let the smallest value of k N , for which the coefficient of x^3 in (1+x)^3 + (1+x)^4 + (1+x)^5 + + (1+x)⁹⁹ + (1+kx)¹⁰⁰ , x 0 , is (43n + 101 4 ) (¹⁰⁰C₃ ) for some n N , be p . The 2026If for 3 r 30 , 30 30-r + 3 30 31-r + 3 30 32-r + 30 33-r = m r , then m equals: 2026 Full Binomial Theorem list All JEE Main PYQs