We have ∑r=06(Cr6⋅C6−r6)=C06⋅C66+C16⋅C56+...+C66⋅C06
Now, we know that the expansion of (1+x)n=C0nx0+C1nx1+C2nx2+...Cnnxn
⇒(1+x)6(1+x)6=(C06+C16x+C26x2+...+C66x6)(C06+C16x+C26x2+...+C66x6)
⇒(1+x)12=(C06+C16x+C26x2+...+C66x6)(C06+C16x+C26x2+...+C66x6)
On comparing the coefficient of x6 both sides, we get
C612=C06⋅C66+C16⋅C56+...+C66⋅C06
⇒C06⋅C66+C16⋅C56+...+C66⋅C06=6!⋅6!12!
⇒C06⋅C66+C16⋅C56+...+C66⋅C06=6×5×4×3×2×1×6!12×11×10×9×8×7×6!
⇒C06⋅C66+C16⋅C56+...+C66⋅C06=924.