Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 202117 MarchEvening Shift
Exam
JEE Main
Year
2021
Date
17 March
Shift
Evening Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2021 · 17 March · Evening Shift · Mathematics · Binomial Theorem

The value of ∑ _ r = 0 ^ 6 (Cr 6 · C6 - r 6) is equal to :

The value of $\mathop{∑}_{r = 0}^{6}\left(Cr 6 \cdot C6 - r 6\right) is equal to :

Options

  1. A11241124
  2. B13241324
  3. C10241024
  4. D924924

Correct answer

D. 924924

Step-by-step solution

We have ∑r=06(Cr6⋅C6−r6)=C06⋅C66+C16⋅C56+...+C66⋅C06\mathop{∑}_{r = 0}^{6}\left(Cr 6 \cdot C6 - r 6\right) = C0 6 \cdot C6 6 + C1 6 \cdot C5 6 + . . . + C6 6 \cdot C0 6

Now, we know that the expansion of (1+x)n=C0nx0+C1nx1+C2nx2+...Cnnxn{\left(1 + x\right)}^{n} = C0 n {x}^{0} + C1 n {x}^{1} + C2 n {x}^{2} + . . . Cn n {x}^{n}

⇒(1+x)6(1+x)6=(C06+C16x+C26x2+...+C66x6)(C06+C16x+C26x2+...+C66x6)⇒ ( 1 + x{)}^{6} ( 1 + x{)}^{6} = \left(C0 6 + C1 6 x + C2 6 {x}^{2} + . . . + C6 6 {x}^{6}\right)\left(C0 6 + C1 6 x + C2 6 {x}^{2} + . . . + C6 6 {x}^{6}\right)

⇒(1+x)12=(C06+C16x+C26x2+...+C66x6)(C06+C16x+C26x2+...+C66x6)⇒ ( 1 + x{)}^{12} = \left(C0 6 + C1 6 x + C2 6 {x}^{2} + . . . + C6 6 {x}^{6}\right)\left(C0 6 + C1 6 x + C2 6 {x}^{2} + . . . + C6 6 {x}^{6}\right)

On comparing the coefficient of x6{x}^{6} both sides, we get

C612=C06⋅C66+C16⋅C56+...+C66⋅C06C6 12 = C0 6 \cdot C6 6 + C1 6 \cdot C5 6 + . . . + C6 6 \cdot C0 6

⇒C06⋅C66+C16⋅C56+...+C66⋅C06=12!6!⋅6!⇒ C0 6 \cdot C6 6 + C1 6 \cdot C5 6 + . . . + C6 6 \cdot C0 6 = \dfrac{12 !}{6 ! \cdot 6 !}

⇒C06⋅C66+C16⋅C56+...+C66⋅C06=12×11×10×9×8×7×6!6×5×4×3×2×1×6!⇒ C0 6 \cdot C6 6 + C1 6 \cdot C5 6 + . . . + C6 6 \cdot C0 6 = \dfrac{12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 !}{6 \times 5 \times 4 \times 3 \times 2 \times 1 \times 6 !}

⇒C06⋅C66+C16⋅C56+...+C66⋅C06=924.⇒ C0 6 \cdot C6 6 + C1 6 \cdot C5 6 + . . . + C6 6 \cdot C0 6 = 924 .

Practice Binomial Theorem on Quantrex Academy →

More from Binomial Theorem

If 26((2^3)/(3) 12 2 + (2^5)/(5) 12 4 + (2^7)/(7) 12 6 + … + 2^ 13 13 12 12 ) = 3^ 13 - α… JEE Main 2026If (1 - x^3)^ 10 = ∑ _ r=0 ^ 10 a_r x^r (1-x)^ 30-2r , then 9a_9 a_ 10 is equal to… JEE Main 2026If the coefficients of the middle terms in the binomial expansions of (1 + α x)^ 26 and… JEE Main 2026The coefficient of x^2 in the expansion of (2x^2 + (1)/(x))^ 10 , x ≠ 0 , is : JEE Main 2026If the sum of the coefficients of x^7 and x^ 14 in the expansion of ((1)/(x^3) - x^4)^n… JEE Main 2026In the expansion of (9x- 1 3 x )^ 18 , x>0 , if the term independent of x is (221)k… JEE Main 2026Let the smallest value of k ∈ ℕ , for which the coefficient of x^3 in (1+x)^3 + (1+x)^4 +… JEE Main 2026If for 3 ≤ r ≤ 30 , 30 30-r + 3 30 31-r + 3 30 32-r + 30 33-r = m r , then m equals: JEE Main 2026The number of elements in the set S = \ (r, k) : k ∈ ℤ and ^ 36 C_ r+1 = 6( ^ 35 C_r)… JEE Main 2026Given below are two statements : Statement I: 25^ 13 +20^ 13 +8^ 13 +3^ 13 is divisible… JEE Main 2026The sum of the coefficients of x^ 499 and x^ 500 in (1+x)^ 1000 +x(1+x)^ 999 +x^ 2 (1+x)^… JEE Main 2026Let S=(1)/(25!)+(1)/(3!23!)+(1)/(5!21!)+… up to 13 terms. If 13 ~S= 2^ k n! , k ∈ ~N… JEE Main 2026The value of ^ 100 C_ 50 51 + ^ 100 C_ 51 52 +….+ ^ 100 C_ 100 101 is : JEE Main 2026The sum of all possible values of n ∈ N , so that the coefficients of x, x^ 2 and x^ 3 in… JEE Main 2026Let C_ r denote the coefficient of x^ r in the binomial expansion of (1+x)^ n , n ∈ N, 0… JEE Main 2026The coefficient of x^ 48 in (1+x)+2(1+x)^ 2 +3(1+x)^ 3 +…+100(1+x)^ 100 is equal to JEE Main 2026 Full Binomial Theorem list Binomial Theorem JEE Maths PYQsJEE Mathematics PYQs All JEE Main PYQs