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JEE Main 202225 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Evening Shift
Subject
Mathematics
Chapter
Circle

JEE Main 2022 · 25 June · Evening Shift · Mathematics · Circle

A circle touches both the y -axis and the line x + y = 0 . Then the...

A circle touches both the yy-axis and the line x+y=0x + y = 0. Then the locus of its centerA circle touches both the y -axis and the line x + y = 0 . Then the locus of its center

Options

  1. Ay=2xy = \sqrt{2}x
  2. Bx=2yx = \sqrt{2}y..
  3. Cy2−x2=2xy{y}^{2} - {x}^{2} = 2xy
  4. Dx2−y2=2xy{x}^{2} - {y}^{2} = 2xy

Correct answer

D. x2−y2=2xy{x}^{2} - {y}^{2} = 2xy

Step-by-step solution

Plotting the diagram of given data we have,A circle touches both the y -axis and the line x + y = 0 . Then the locus of its center

Now to find locus, let centre be (h,k)\left(h, k\right). According to question

\left|OM\right| = ∣ON∣\left|ON\right| distance

⇒⇒∣h∣=∣h+k∣2\left|h\right| = \dfrac{\left|h + k\right|}{\sqrt{2}}

squaring both sides we get

⇒2h2=(h+k)2⇒ 2{h}^{2} = {\left(h + k\right)}^{2}

⇒2h2=h2+k2+2hk⇒ 2{h}^{2} = {h}^{2} + {k}^{2} + 2hk

Replacing hh with xx & kk with yy we get

2x2=x2+y2+2xy2{x}^{2} = {x}^{2} + {y}^{2} + 2xy

⇒x2−y2=2xy⇒ {x}^{2} - {y}^{2} = 2xy

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