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JEE Main 201910 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
10 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Circle

JEE Main 2019 · 10 April · Morning Shift · Mathematics · Circle

If the circles x ^ 2 + y ^ 2 + 5Kx + 2y + K = 0 and 2( x ^ 2 + y ^...

If the circles x2+y2+5Kx+2y+K=0{x}^{2} + {y}^{2} + 5Kx + 2y + K = 0 and 2(x2+y2)+2Kx+3y−1=0,(K∈R)2\left({x}^{2} + {y}^{2}\right) + 2Kx + 3y - 1 = 0, \left(K \in R\right), intersect at the points P and Q, then the line 4x+5y−K=04x + 5y - K = 0, passes through PP and Q,Q, for:

Options

  1. Aexactly two values of KK
  2. Bno value of KK
  3. Cexactly one value of KK
  4. Dinfinitely many values of KK

Correct answer

B. no value of KK

Step-by-step solution

S1=x2+y2+5Kx+2y+K=0{S}_{1} = {x}^{2} + {y}^{2} + 5Kx + 2y + K = 0

S2=x2+y2+Kx+y2+12=0{S}_{2} = {x}^{2} + {y}^{2} + Kx + \dfrac{y}{2} + \dfrac{1}{2} = 0

∴∴ Equation of common chord is S1−S2=0{S}_{1} - {S}_{2} = 0

⇒4Kx+32y+⇒ 4Kx + \dfrac{3}{2}y +\left(K - \dfrac{1}{2}\right) = 0 . . . . (1)\left(1\right)
Give equation of common chord is 4x−5y−K=0....(2)4x - 5y - K = 0 . . . . \left(2\right)

∵(1) and (2)∵ \left(1\right) \text{ and } \left(2\right) are identical
∴4K4=32−5=K−12−K∴ \dfrac{4K}{4} = \dfrac{\dfrac{3}{2}}{- 5} = \dfrac{K - \dfrac{1}{2}}{- K}

Clearly, no value of KK satisfy simultaneously.

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