JEE Main 2019 · 12 January · Morning Shift · Mathematics · Circle
If a variable line 3x + 4y - λ = 0 is such that the two circles x ^...
If a variable line 3x+4y−λ=0 is such that the two circles x2+y2−2x−2y+1=0 and x2+y2−18x−2y+78=0 are on its opposite sides, then the set of all values of λ is the interval :
Options
A[13,23]
B(23,31)
C[12,21]
D(2,17)
Correct answer
C. [12,21]
Step-by-step solution
Given circles x2+y2−2x−2y+1=0⇒(x−1)2+(y−1)2=12 and
x2+y2−18x−2y+78=0⇒(x−9)2+(y−1)2=22
Thus, centers of two circles are \left(1, 1\right) \text{ and } \left(9, 1\right)andradiiare1 \text{ and } 2respectively.</p><p>Since,centerofcirclesareontheoppositesideofline3x + 4y - \lambda = 0.</p><p>⇒ \left(3 + 4 - \lambda\right)\left(27 + 4 - \lambda\right) < 0</p><p>⇒ \left(7 - \lambda\right)\left(31 - \lambda\right) < 0</p><p>⇒ \lambda \in \left(7, 31\right) \ldots \ldots . \left(i\right)<br/><br/>Since,circlesshouldnotintersectgivenline.</p><p>Hence,32+427−λ≥1 and 32+4231−λ≥2
⇒∣7−λ∣≥5 and ∣31−λ∣≥10
⇒λ≤2 or λ≥12…….(ii)
and λ≤21 or λ≥41…….(iii)</p><p>Thus,\lambda \in \left(i\right) \cap \left(ii\right) \cap \left(iii\right)