JEE Main2013MathematicsCircleActual
If the circle x^2+y^2-6 x-8 y+ (25-a^2 )=0 touches the axis of x , then a equals.
Options
- A0
- B4
- C2
- D3
Correct answer
B. 4
Step-by-step solution
aligned & x^2+y^2-6 x-8 y+ (25-a^2 )=0 & Radius =4= 9+16+ (25-a^2 ) & a = 4 aligned