JEE Main2012MathematicsCircleActual
If the line y=m x+1 meets the circle x^2+y^2+3 x=0 in two points equidistant from and on opposite sides of x -axis, then
Options
- A3 m+2=0
- B3 m-2=0
- C2 m+3=0
- D2 m-3=0
Correct answer
B. 3 m-2=0
Step-by-step solution
Circle: x^2+y^2+3 x=0 Centre, B= (- 3 2 , 0 ) y -intercept of the line =1 A =(0,1) Slope of line, m= = O A O B aligned & m= 1 3 2 = 2 3 & 3 m-2=0 aligned