JEE Main202622 January 2026Evening ShiftMathematicsComplex NumberActual

Let S= z C : 4 z²+ z =0 . Then _ z S |z|² is equal to:

Options

A5 64
B1 16
C3 16
D7 64

Correct answer

C. 3 16

Step-by-step solution

Let z=x+iy . From 4z^2+ z =0 , separating real and imaginary parts: Real: 4x^2-4y^2+x=0 , Imaginary: y(8x-1)=0 . Case 1: y=0 x(4x+1)=0 z=0 or z=- 1 4 . Case 2: x= 1 8 1 16 -4y^2+ 1 8 =0 y^2= 3 64 . So |z|^2= 1 64 + 3 64 = 1 16 . |z|^2=0+ 1 16 + 1 16 + 1 16 = 3 16

Practice Complex Number on Quantrex Academy →

More from Complex Number

The number of values of z C , satisfying the equations |z-(4+8i)|= 10 and |z-(3+5i)|+|z-(5+11i)|=4 5 , is: 2026 Let S = z C : z^2 + 6 ,iz - 3 = 0 . Then _ z S z^8 is equal to : 2026 Let the set of all values of k R such that the equation z( z + 2 + i) + k(2 + 3i) = 0 , z C , has at least one solution, be the interval [ , ] . Then 9( + ) is equal to: 2026 Let z₁, z₂ C be the distinct solutions of the equation z^2 + 4z - (1 + 12i) = 0 . Then |z₁|^2 + |z₂|^2 is equal to : 2026 Let S= z C : z^2+4z+16=0 . Then _ z S |z+ 3 i|^2 is equal to: 2026 Let z be a complex number such that |z+2| = |z-2| and ( z+3 z-i ) = 4 . Then |z|^2 is equal to: 2026 Let the circles C₁ : |z| = r and C₂ : |z - 3 - 4i| = 5 , z C , be such that C₂ lies within C₁ . If z₁ moves on C₁ , z₂ moves on C₂ and |z₁ - z₂| = 2 , then |z₁ - z₂| is equal to: 2026 Let x and y be real numbers such that 50 ( 2x 1+3i - y 1-2i ) = 31 + 17i , i = -1 . Then the value of 10(x - 3y) is : 2026 Full Complex Number list All JEE Main PYQs