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JEE Main 202311 AprilMorning Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2023 · 11 April · Morning Shift · Mathematics · Complex Number

Let w _ 1 be the point obtained by the rotation of z _ 1 = 5 + 4i...

Let w1{w}_{1} be the point obtained by the rotation of z1=5+4i{z}_{1} = 5 + 4i about the origin through a right angle in the anticlockwise direction, and w2{w}_{2} be the point obtained by the rotation of z2=3+5i{z}_{2} = 3 + 5i about the origin through a right angle in the clockwise direction. Then the principal argument w1−w2{w}_{1} - {w}_{2} is equal to

Options

  1. Aπ−tan⁡−189\pi - \tan^{- 1}\dfrac{8}{9}
  2. B−π+tan⁡−1335- \pi + \tan^{- 1}\dfrac{33}{5}
  3. C−π+tan⁡−189- \pi + \tan^{- 1}\dfrac{8}{9}
  4. Dπ−tan⁡−1335\pi - \tan^{- 1}\dfrac{33}{5}

Correct answer

A. π−tan⁡−189\pi - \tan^{- 1}\dfrac{8}{9}

Step-by-step solution

Given,

Two complex numbers w1 and w2{w}_{1} \text{ and } {w}_{2}

w1=3+5i{w}_{1} = 3 + 5i and w2=5+4i{w}_{2} = 5 + 4i are both rotated by 90°{90}^{°} with respect to origin anticlock-wise and clockwise respectively,

So by concept of rotation we get,

w3=iw1=i(3+5i)=−5+3i{w}_{3} = i{w}_{1} = i\left(3 + 5i\right) = - 5 + 3i

And w4=−iw2=−i(5+4i)=4−5i{w}_{4} = - i{w}_{2} = - i\left(5 + 4i\right) = 4 - 5i

Now principal argument of w3−w4=−9+8i{w}_{3} - {w}_{4} = - 9 + 8i will be π−tan⁡−189\pi - \tan^{- 1}\dfrac{8}{9} {as complex number is in second quadrant so principal argument is given by π−tan⁡−1∣yx∣\pi - \tan^{- 1}\left|\dfrac{y}{x}\right|}

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