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JEE Main 202127 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Morning Shift
Subject
Mathematics
Chapter
Complex Number

JEE Main 2021 · 27 July · Morning Shift · Mathematics · Complex Number

Let C be the set of all complex numbers. Let S _ 1 = \ z ∈ C | |z –...

Let CC be the set of all complex numbers. Let

S1={z∈C∣∣z–3–2i∣2=8},{S}_{1} = \left\{z \in C | {\left|z – 3 – 2i\right|}^{2} = 8\right\},

S2=z∈C∣Re(z)≥5{S}_{2} = z \in C | Re\left(z\right) \ge 5 and

S3={z∈C∣∣z–z¯∣≥8}.{S}_{3} = \left\{z \in C | \left|z – \overset{¯}{z}\right| \ge 8\right\} .

Then the number of elements in S1∩S2∩S3{S}_{1} \cap {S}_{2} \cap {S}_{3} is equal to

Let C be the set of all complex numbers. Let S _ 1 = \ z ∈ C | |z – 3 – 2i| ^ 2 = 8\ , S _ 2 = z ∈ C | Re(z) ≥ 5 and S

Options

  1. A11
  2. B00
  3. C22
  4. DInfinite

Correct answer

A. 11

Step-by-step solution

S1:∣z−3−2i∣2=8{S}_{1}: {\left|z - 3 - 2i\right|}^{2} = 8

⇒∣z−3−2i∣=22⇒ \left|z - 3 - 2i\right| = 2\sqrt{2}

⇒(x−3)2+(y−2)2=(22)2⇒ {\left(x - 3\right)}^{2} + {\left(y - 2\right)}^{2} = {\left(2\sqrt{2}\right)}^{2} (Put z=x+iyz = x + iy)

S2:x≥5{S}_{2}: x \ge 5

S3:∣z−z¯∣≥8{S}_{3}: \left|z - \overset{¯}{z}\right| \ge 8 (put z=x+iyz = x + iy)

⇒∣2iy∣≥8⇒ \left|2iy\right| \ge 8

⇒2∣y∣≥8∴y≥4,y≤−4⇒ 2\left|y\right| \ge 8 ∴ y \ge 4, y \le - 4

So, the required diagram is

Let C be the set of all complex numbers. Let S _ 1 = \ z ∈ C | |z – 3 – 2i| ^ 2 = 8\ , S _ 2 = z ∈ C | Re(z) ≥ 5 and S

Hence, n(S1∩S2∩S3)=1n\left({S}_{1} \cap {S}_{2} \cap {S}_{3}\right) = 1

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