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JEE Main2005MathematicsComplex NumberActual

If the cube roots of unity are 1, , ^2 then the roots of the equation (x-1)^3+8=0 , are

Options

  1. A-1,-1+2 ,-1-2 ^2
  2. B-1,-1,-1
  3. C-1,1-2 , 1-2 ^2
  4. D-1,1+2 , 1+2 ^2

Correct answer

C. -1,1-2 , 1-2 ^2

Step-by-step solution

(x-1)^3+8=0 (x-1)=(-2)(1)^ 1 / 3 x-1=-2 or -2 or -2 ^2 or n=-1 or 1-2 or 1-2 ^2 .

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