Let
I=∫−π/4π/41+esinx32cos4xdxUsing the definite integral property
∫−aaf(x)dx=∫0a(f(x)+f(−x))dx, we get:
I=∫0π/4(1+esinx32cos4x+1+esin(−x)32cos4(−x))dxI=∫0π/4(1+esinx32cos4x+1+e−sinx32cos4x)dxI=∫0π/4(1+esinx32cos4x+esinx+132cos4x⋅esinx)dxI=∫0π/432cos4x(1+esinx1+esinx)dxI=∫0π/432cos4xdxUsing the trigonometric identity
cos2x=21+cos2x, we can write:
cos4x=(21+cos2x)2=41(1+2cos2x+cos22x)cos4x=41(1+2cos2x+21+cos4x)=83+21cos2x+81cos4xSubstituting this back into the integral:
I=32∫0π/4(83+21cos2x+81cos4x)dxI=∫0π/4(12+16cos2x+4cos4x)dxIntegrating term by term:
I=[12x+8sin2x+sin4x]0π/4I=(12(4π)+8sin(2π)+sin(π))−(0+0+0)I=3π+8(1)+0=3π+8Answer:
3π+8