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AP EAMCET202124 Aug 2021Evening ShiftChemistryCoordination CompoundsActual

The geometries of [ Ni ( CO )₄ ], [ PtCl ₄ ]²⁻ and [ Co ( NH ₃ )₆ ]³⁺ respectively are

Options

  1. Atetrahedral, tetrahedral and octahedral
  2. Btetrahedral, square planar and square pyramidal
  3. Csquare planar, square planar and octahedral
  4. Dtetrahedral, square planar and octahedral

Correct answer

D. tetrahedral, square planar and octahedral

Step-by-step solution

[ Ni ( CO )₄ ] Ground state electronic configuration =3 d^8 4 s^2 CO is strong field ligand, so it pushes 10 e⁻ to 3 d -orbital. The hybridisation of [ Ni ( CO )₄ ] is s p^3 and geometry is tetrahedral. [ PtCl ₄ ]²⁻ Square planar. A strong repulsion with the electron and ligand take place in between platinum which leads to strong field splitting due to which square planar geometry is more stabilised than tetrahedral shape. [ Co ( NH ₃ )₆ ]³⁺ is octahedral that involves d^2 s p^3 hybridisation.

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