AP EAMCET202124 Aug 2021Evening ShiftChemistryCoordination CompoundsActual
The geometries of [ Ni ( CO )₄ ], [ PtCl ₄ ]²⁻ and [ Co ( NH ₃ )₆ ]³⁺ respectively are
Options
- Atetrahedral, tetrahedral and octahedral
- Btetrahedral, square planar and square pyramidal
- Csquare planar, square planar and octahedral
- Dtetrahedral, square planar and octahedral
Correct answer
D. tetrahedral, square planar and octahedral
Step-by-step solution
[ Ni ( CO )₄ ] Ground state electronic configuration =3 d^8 4 s^2 CO is strong field ligand, so it pushes 10 e⁻ to 3 d -orbital. The hybridisation of [ Ni ( CO )₄ ] is s p^3 and geometry is tetrahedral. [ PtCl ₄ ]²⁻ Square planar. A strong repulsion with the electron and ligand take place in between platinum which leads to strong field splitting due to which square planar geometry is more stabilised than tetrahedral shape. [ Co ( NH ₃ )₆ ]³⁺ is octahedral that involves d^2 s p^3 hybridisation.