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JEE Main 202622 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Determinants

JEE Main 2026 · 22 January · Evening Shift · Mathematics · Determinants

Let n be the number obtained on rolling a fair die. If the...

Let n be the number obtained on rolling a fair die. If the probability that the system
x−ny+z=6x-\mathrm{n} y+z=6
x+(n−2)y+(n+1)z=8x+(\mathrm{n}-2) y+(\mathrm{n}+1) z=8
(n−1)y+z=1(\mathrm{n}-1) y+z=1 has a unique solution is k6\frac{k}{6},
then the sum of kk and all possible values of nn is :

Options

  1. A20
  2. B24
  3. C21
  4. D22

Correct answer

D. 22

Step-by-step solution

The coefficient matrix has determinant det⁡(A)=−(n−1)(n−2)\det(A) = -(n-1)(n-2).
The system has a unique solution when det⁡(A)≠0\det(A) \neq 0, which requires n≠1n \neq 1 and n≠2n \neq 2.
For a fair die, n∈{1,2,3,4,5,6}n \in \{1,2,3,4,5,6\}, so the unique solution occurs for n∈{3,4,5,6}n \in \{3,4,5,6\}.
The probability is 46=23\frac{4}{6} = \frac{2}{3}, giving k=4k = 4.
The sum of kk and all possible values of nn where unique solution exists is 4+(3+4+5+6)=224 + (3+4+5+6) = 22.
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