- Exam
- JEE Main
- Year
- 2019
- Date
- 10 April
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Determinants
JEE Main 2019 · 10 April · Evening Shift · Mathematics · Determinants
Let λ be a real number for which the system of linear equations x +...
Let be a real number for which the system of linear equations
and
has infinitely many solutions. Then is a root of the quadratic equation:
Options
- A
- B
- C
- D
Correct answer
B.
Step-by-step solution
The system of equations and have a infinitely many solution, if
D = \left|\begin{cases}{a}_{1} & {b}_{1} & {c}_{1} \\ {a}_{2} & {b}_{2} & {c}_{2} \\ {a}_{3} & {b}_{3} & {c}_{3}\end{cases}\right| = 0, {D}_{1} = \left|\begin{cases}{d}_{1} & {b}_{1} & {c}_{1} \\ {d}_{2} & {b}_{2} & {c}_{2} \\ {d}_{3} & {b}_{3} & {c}_{3}\end{cases}\right| = 0, {D}_{2} = \left|\begin{cases}{a}_{1} & {d}_{1} & {c}_{1} \\ {a}_{2} & {d}_{2} & {c}_{2} \\ {a}_{3} & {d}_{3} & {c}_{3}\end{cases}\right| = 0 and {D}_{3} = \left|\begin{cases}{a}_{1} & {b}_{1} & {d}_{1} \\ {a}_{2} & {b}_{2} & {d}_{2} \\ {a}_{3} & {b}_{3} & {d}_{3}\end{cases}\right| = 0 .
Thus, for infinitely many solutions, we have
⇒ \left|\begin{cases}1 & 1 & 1 \\ 4 & \lambda & - \lambda \\ 3 & 2 & - 4\end{cases}\right| = 0
And, satisfies the equation