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JEE Main 201412 AprilOnline
Exam
JEE Main
Year
2014
Date
12 April
Mode
Online
Subject
Mathematics
Chapter
Determinants

JEE Main 2014 · 12 April · Online · Mathematics · Determinants

If aligned &. array ccc a^2 & b^2 & c^2 (a+λ)^2 & (b+λ)^2 & (c+λ^2)...

If \begin{aligned} &\left.\mid \begin{array}{ccc} a^2 & b^2 & c^2 \\ (a+\lambda)^2 & (b+\lambda)^2 & \left(c+\lambda^2\right) \\ (a-\lambda)^2 & \left(b-\lambda^2\right) & \left(-\lambda^2\right. \end{array}\right) \\ &=k \lambda\left|\begin{array}{ccc} a^2 & b^2 & c^2 \\ a & b & c \\ 1 & 1 & 1 \end{array}\right|, \lambda \neq 0 \end{aligned}$$thenthen\mathrm{k}$ is equal to:

Options

  1. A4λabc4 \lambda \mathrm{abc}
  2. B−4λabc-4 \lambda \mathrm{abc}
  3. C4λ24 \lambda^2
  4. D−4λ2-4 \lambda^2

Correct answer

C. 4λ24 \lambda^2

Step-by-step solution

Let \Delta=\left|a2b2c2(a+λ)2(b+λ)2(c+λ)2(a−λ)2(b−λ)2(c−λ)2\begin{array}{ccc}a^2 & b^2 & c^2 \\ (a+\lambda)^2 & (b+\lambda)^2 & (c+\lambda)^2 \\ (a-\lambda)^2 & (b-\lambda)^2 & (c-\lambda)^2\end{array}\right| \begin{aligned} &\text { Apply } \mathrm{R}_2 \rightarrow \mathrm{R}_2-\mathrm{R}_3 \\ &\Delta=\left|\begin{array}{ccc} a^2 & b^2 & c^2 \\ (a+\lambda)^2-(a-\lambda)^2 & (b+\lambda)^2-(b-\lambda)^2 & (c+\lambda)^2-(c-\lambda)^2 \\ (a-\lambda)^2 & (b-\lambda)^2 & (c-\lambda)^2 \end{array}\right| \\ &=\left|\begin{array}{ccc} a^2 & b^2 & c^2 \\ 4 a \lambda & 4 b \lambda & 4 c \lambda \\ (a-\lambda)^2 & (b-\lambda)^2 & (c-\lambda)^2 \end{array}\right| \\ &\left(\because(x+y)^2-(x-y)^2=4 x y\right) \\ & \end{aligned}$ Taking out 4 common from $\mathrm{R}_2$ $=4\left|\begin{array}{ccc}a^2 & b^2 & c^2 \\ a \lambda & b \lambda & c \lambda \\ a^2+\lambda^2-2 a \lambda & b^2+\lambda^2-2 b \lambda & c^2+\lambda^2-2 c \lambda\end{array}\right|$  Apply R3→[R3−(R1−2R2)]=4∣a2b2c2aλbλcλλ2λ2λ2∣\begin{aligned} &\text { Apply } \mathrm{R}_3 \rightarrow\left[\mathrm{R}_3-\left(\mathrm{R}_1-2 \mathrm{R}_2\right)\right] \\ &=4\left|\begin{array}{lll} a^2 & b^2 & c^2 \\ a \lambda & b \lambda & c \lambda \\ \lambda^2 & \lambda^2 & \lambda^2 \end{array}\right| \end{aligned}TakingoutTaking out\lambdacommonfromcommon from\mathrm{R}_2andand\lambda^2fromfrom\mathrm{R}_3..=4 \lambda\left(\lambda^2\right)\left|a2b2c2abc111\begin{array}{ccc} a^2 & b^2 & c^2 \\ a & b & c \\ 1 & 1 & 1 \end{array}\right|=kλ∣a2b2c2abc111∣⇒k=4λ2\begin{aligned} &=k \lambda\left|\begin{array}{ccc} a^2 & b^2 & c^2 \\ a & b & c \\ 1 & 1 & 1 \end{array}\right| \\ &\Rightarrow k=4 \lambda^2 \end{aligned}$$
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