If y α = 2 t a n α + c o t α 1 + t a n 2 α + 1 s i n 2 α , α ∈ 3 π 4 , π , then d y d α at α = 5 π 6 is

Step-by-step solution

Simplifying using Trigonometric Identity, we get, y α = 1 + cot α or, y α = - 1 + cot α , as α ∈ 3 π 4 , π Hence, d y d α = cos e c 2 α ∴   d y d α α = 5 π 6 = 4