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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Differentiation

JEE Main 2020 · 7 January · Morning Shift · Mathematics · Differentiation

If y(α) = 2( tanα + cotα 1 + ta n ^ 2 α ) + 1 si n ^ 2 α , α ∈...

If y(α)=2(tanα+cotα1+tan2α)+1sin2α,α∈(3π4,π)y\left(\alpha\right) = \sqrt{2\left(\dfrac{tan\alpha + cot\alpha}{1 + ta{n}^{2}\alpha}\right) + \dfrac{1}{si{n}^{2}\alpha}}, \alpha \in \left(\dfrac{3\pi}{4}, \pi\right), then dydα\dfrac{dy}{d\alpha} at α=5π6\alpha = \dfrac{5\pi}{6} is

Options

  1. A44
  2. B43\dfrac{4}{3}
  3. C−4- 4
  4. D−14- \dfrac{1}{4}

Correct answer

A. 44

Step-by-step solution

Simplifying using Trigonometric Identity, we get,

y(α)=∣1+cot⁡(α)∣y\left(\alpha\right) = \left|1 + \cot \left(\alpha\right)\right|

or, y(α)=−(1+cot⁡(α))y\left(\alpha\right) = - \left(1 + \cot \left(\alpha\right)\right), as α∈(3π4,π)\alpha \in \left(\dfrac{3\pi}{4}, \pi\right)

Hence, dydα=cosec2α\dfrac{dy}{d\alpha} = cose{c}^{2}\alpha

∴dydαα=5π6=4{∴ \dfrac{dy}{d\alpha}}_{\alpha = \dfrac{5\pi}{6}} = 4

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