Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main 20254 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
4 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Functions

JEE Main 2025 · 4 April · Morning Shift · Mathematics · Functions

Let f: ℝ arrow ℝ be a continuous function satisfying f(0)=1 and f(2...

Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} be a continuous function satisfying f(0)=1f(0)=1 and f(2x)−f(x)=xf(2 \mathrm{x})-f(\mathrm{x})=\mathrm{x} for all x∈R\mathrm{x} \in \mathbb{R}. If lim⁡n→∞\lim _{n \rightarrow \infty}\left\{f(x)-f\left(\frac{x}{2^n}\right)\right\}=G(x), then ∑r=110G(r2)\sum_{r=1}^{10} G\left(r^2\right) is equal to

Options

  1. A540
  2. B385
  3. C420
  4. D215

Correct answer

B. 385

Step-by-step solution

<br/>f(2x)−f(x)=xf(x)−f(x2)=x2f(x2)−f(x4)=x4f(x4)−f(x8)=x8f(x2n−1)−f(x2n)=x2nf(2x)−f(x2n)=x{1−(12)n−11−12}f(x)−f(x2n)=2x(1−(12)n+1)f(x)+x−f(x2n)=2x(1−(12)n+1)lim⁡n→∞(f(x)−f(x2n))=lim⁡n→∞(2x(1−(12)n+1)−x)G(x)=x∑r=110G(r2)=∑r=110r2=385<br/>\begin{aligned}<br/>& f(2 x)-f(x)=x \\ & f(x)-f\left(\frac{x}{2}\right)=\frac{x}{2} \\ & \mathrm{f}\left(\frac{\mathrm{x}}{2}\right)-\mathrm{f}\left(\frac{\mathrm{x}}{4}\right)=\frac{\mathrm{x}}{4} \\ & \mathrm{f}\left(\frac{\mathrm{x}}{4}\right)-\mathrm{f}\left(\frac{\mathrm{x}}{8}\right)=\frac{\mathrm{x}}{8} \\ & f\left(\frac{x}{2^{n-1}}\right)-f\left(\frac{x}{2^n}\right)=\frac{x}{2^n} \\ & f(2 x)-f\left(\frac{x}{2^n}\right)=x\left\{\frac{1-\left(\frac{1}{2}\right)^{n-1}}{1-\frac{1}{2}}\right\} \\ & f(x)-f\left(\frac{x}{2^n}\right)=2 x\left(1-\left(\frac{1}{2}\right)^{n+1}\right) \\ & \mathrm{f}(\mathrm{x})+\mathrm{x}-\mathrm{f}\left(\frac{\mathrm{x}}{2^{\mathrm{n}}}\right)=2 \mathrm{x}\left(1-\left(\frac{1}{2}\right)^{\mathrm{n}+1}\right) \\ & \lim _{n \rightarrow \infty}\left(f(x)-f\left(\frac{x}{2^n}\right)\right)=\lim _{n \rightarrow \infty}\left(2 x\left(1-\left(\frac{1}{2}\right)^{n+1}\right)-x\right) \\ & G(x)=x \\ & \sum_{r=1}^{10} G\left(r^2\right)=\sum_{r=1}^{10} r^2=385<br/>\end{aligned}
Practice Functions on Quantrex Academy →

More from Functions

Let ℕ denote the set of all positive integers. Consider the sets A = \ 1, 2, 3, 4, 5\ and… JEE Advanced 2026Let f:(1,∞)→ℝ be a function defined as f(x) = (x-1)/(x+1) . Let f^ i+1 (x) = f(f^i(x))… JEE Main 2026Let f be a polynomial function such that _2(f(x)) = ( _2(2+(2)/(3)+(2)/(9)+…∞))·… JEE Main 2026Let f: ℝ arrow ℝ be defined as f(x) = (2x^2 - 3x + 2)/(3x^2 + x + 3) . Then f is : JEE Main 2026Let e be the base of natural logarithm and let f: \ 1, 2, 3, 4\ arrow \ 1, e, e^2, e^3\… JEE Main 2026Let f: R arrow R be a function such that f(x) + 3f((π)/(2) - x) = x , x ∈ R . Let the… JEE Main 2026The sum of all the integral values of p such that the equation 3 ^2 x + 12 x - 3 = p , x… JEE Main 2026Let A = \ 1, 2, 3, 4, 5, 6\ . The number of one-one functions f: A arrow A such that f(1)… JEE Main 2026For the function f:[1,∞) arrow [1,∞) defined by f(x)=(x-1)^4+1 , among the two… JEE Main 2026Let for some α ∈ ℝ , f:ℝarrowℝ be a function satisfying f(x+y)=f(x)+2y^2+y+α xy for all… JEE Main 2026Let [·] denote the greatest integer function. If the domain of the function f(x) = ^ -1… JEE Main 2026The number of functions f: \ 1, 2, 3, 4\ arrow \ a, b, c\ , which are not onto, is: JEE Main 2026If the domain of the function f(x) = _ (0.6) (|(2x-5)/(x^2-4)|) is (-∞, a] \ b\ [c, d)… JEE Main 2026Given below are two statements: Statement I: The function f: R arrow R defined by… JEE Main 2026The sum of all the elements in the range of f(x)=Sgn( x)+Sgn( x)+Sgn( x)+Sgn( x) , x ≠ n… JEE Main 2026If g(x)=3 x^ 2 +2 x-3, f(0)=-3 and 4 g(f(x))=3 x^ 2 -32 x+72 , then f(g(2)) is equal to: JEE Main 2026 Full Functions list Functions JEE Maths PYQsJEE Mathematics PYQs All JEE Main PYQs