JEE Main202430 Jan 2024Evening ShiftMathematicsFunctionsActual
Let f : R → R be a function defined f x = x 1 + x 4 1 / 4 and g x = f f f f x then 18 ∫ 0 2 5 x 2 g x d x
Options
- A33
- B36
- C42
- D39
Correct answer
D. 39
Step-by-step solution
Given, f x = x 1 + x 4 1 / 4 Now, finding f o f x = f x 1 + f 4 x 1 / 4 = x 1 + x 4 1 / 4 1 + x 4 1 + x 4 1 / 4 = x 1 + 2 x 4 1 / 4 And f f f x = f x 1 + 2 f 4 x 1 / 4 = x 1 + x 4 1 / 4 1 + 2 x 4 1 + x 4 1 / 4 = x 1 + 3 x 4 1 / 4 ⇒ f f f f x = x 1 + 4 x 4 1 / 4 = g x Now finding, 18 ∫ 0 2 5 x 2 g x d x = 18 ∫ 0 2 5 x 3 1 + 4 x 4 1 / 4 d x Let 1 + 4 x 4 = t 4 ⇒ 16 x 3 d x = 4 t 3 d t So, the integral becomes 18 4 ∫ 1 3 t 3 dt t = 9 2 ∫ 1 3 t 2 dt = 9 2 t 3 3 1 3 = 3 2 · 26 = 39