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JEE Main 202311 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Functions

JEE Main 2023 · 11 April · Evening Shift · Mathematics · Functions

The domain of the function f(x) = 1 [x] ^ 2 - 3[x] - 10 is (where [...

The domain of the function f(x)=1[x]2−3[x]−10f\left(x\right) = \dfrac{1}{\sqrt{{\left[x\right]}^{2} - 3\left[x\right] - 10}} is (where [x][ x ] denotes the greatest integer less than or equal to xx)

Options

  1. A(−∞,−3]∪(5,∞)( - \infty , - 3 ] \cup ( 5, \infty )
  2. B(−∞,−2)∪[6,∞)( - \infty , - 2 ) \cup [ 6, \infty )
  3. C(−∞,−2)∪(5,∞)( - \infty , - 2 ) \cup ( 5, \infty )
  4. D(−∞,−3]∪[6,∞)( - \infty , - 3 ] \cup [ 6, \infty )

Correct answer

B. (−∞,−2)∪[6,∞)( - \infty , - 2 ) \cup [ 6, \infty )

Step-by-step solution

Given:

f(x)=1[x]2−3[x]−10f\left(x\right) = \dfrac{1}{\sqrt{{\left[x\right]}^{2} - 3\left[x\right] - 10}}</p><p>For</p><p>Forf\left(x\right)tobedefined,</p><p>to be defined,</p><p>{\left[x\right]}^{2} - 3\left[x\right] - 10 > 0</p><p></p><p>⇒ \left(\left[x\right] - 5\right)\left(\left[x\right] + 2\right) > 0</p><p></p><p>⇒ \left[x\right] 5</p><p></p><p>⇒ x < - 2 \text{andand} x \ge 6</p><p>So,domainis(−∞,−2)∪[6,∞)</p><p>So, domain is \left(- \infty , - 2\right) \cup [ 6, \infty ).

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