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AP EAMCET202125 Aug 2021Morning ShiftChemistryd and f Block ElementsActual

Among the following options, identify the one which exhibits the greatest number of oxidation states.

Options

  1. AFe
  2. BMn
  3. CCr
  4. DV

Correct answer

B. Mn

Step-by-step solution

Fe (Z=26)=[ Ar ] 4 s^2 3 d^6 ( Highest oxidation state of Fe is +3 ) Mn (Z=25)=[ Ar ] 4 s^2 3 d^5 (5 unpaired electrons in 3 d -orbital and 2 e⁻ in 4 s .) Mn can show 6 oxidation states from MnO to MnO ₄⁻ . Cr ( Z =24)=[ Ar ] 4 s^1 3 d^5 ( Highest oxidation state of Cr is +3 ) V (Z=23)=[ Ar ] 3 d^3 4 s^2 ( Highest oxidation state of V is +2 ) Hence, greatest number of oxidation state is shown by Mn.

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