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JEE Main 202118 MarchMorning Shift
Exam
JEE Main
Year
2021
Date
18 March
Shift
Morning Shift
Subject
Mathematics
Chapter
Functions

JEE Main 2021 · 18 March · Morning Shift · Mathematics · Functions

If the functions are defined as f ( x ) = x and g ( x ) = 1 - x ,...

If the functions are defined as f(x)=xandf ( x ) = \sqrt{x} andg ( x ) = \sqrt{1 - x},thenwhatisthecommondomainofthefollowingfunctions:then what is the common domain of the following functions:f + g, f - g, f / g, g / f, g - f,where(f±g)(x)=f(x)±g(x),(f/g)(x)=f(x)g(x), where \left(f \pm g\right)\left(x\right) = f\left(x\right) \pm g\left(x\right), \left(f / g\right)\left(x\right) = \dfrac{f ( x )}{g ( x )}

Options

  1. A0≤x≤10 \le x \le 1
  2. B0≤x<10 \le x < 1
  3. C0<x<10 < x < 1
  4. D0<x≤10 < x \le 1

Correct answer

C. 0<x<10 < x < 1

Step-by-step solution

f(x)+g(x)=x+1−x,f ( x ) + g ( x ) = \sqrt{x} + \sqrt{1 - x}, domain \left[0, 1\right]</p><p></p><p>f ( x ) - g ( x ) = \sqrt{x} - \sqrt{1 - x},domain[0,1]domain \left[0, 1\right]

g(x)−f(x)=1−x−x,g ( x ) - f ( x ) = \sqrt{1 - x} - \sqrt{x}, domain \left[0, 1\right]</p><p></p><p>\dfrac{f ( x )}{g ( x )} = \dfrac{\sqrt{x}}{\sqrt{1 - x}},domaindomain[ 0, 1 )</p><p></p><p>\dfrac{g ( x )}{f ( x )} = \dfrac{\sqrt{1 - x}}{\sqrt{x}},domaindomain( 0, 1 ]</p><p>So,commondomainis(0,1)</p><p>So, common domain is \left(0, 1\right)

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