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JEE Main20253 Apr 2025Evening ShiftMathematicsHyperbolaActual

If the equation of the hyperbola with foci (4,2) and (8,2) is 3 x^2-y^2- x+ y+ =0 , then + + is equal to _____.

Correct answer

0

Step-by-step solution

Equation of hyperbola is (x-6)^2 a^2 - (y-2)^2 4-a^2 =1 (4- a ^2 )( x -6)^2- a ^2( y -2)^2= a ^2 (4- a ^2 ) comparing with 3 x^2-y^2- x+ y+ =0 , we get a ^2=1 and =36, =4 and =101 + + =141

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