JEE Main 202125 FebruaryEvening Shift
- Exam
- JEE Main
- Year
- 2021
- Date
- 25 February
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Hyperbola
JEE Main 2021 · 25 February · Evening Shift · Mathematics · Hyperbola
A hyperbola passes through the foci of the ellipse x ^ 2 25 + y ^ 2...
A hyperbola passes through the foci of the ellipse and its transverse and conjugate axes coincide with major and minor axes of the ellipse, respectively. If the product of their eccentricities is one, then the equation of the hyperbola is:
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
For ellipse
for hyperbola
Let hyperbola be
it passes through \left(3, 0\right) ⇒ \dfrac{9}{{a}^{2}} = 1⇒ {a}^{2} = 9⇒ {b}^{2} = {a}^{2}\left({e}^{2} - 1\right)
= 9 \left(\dfrac{25}{9} -1\right)
Hyperbola is
option \left(1\right)