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JEE Main 201912 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
12 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Hyperbola

JEE Main 2019 · 12 April · Morning Shift · Mathematics · Hyperbola

Let P be the point of intersection of the common tangents to the...

Let PP be the point of intersection of the common tangents to the parabola y2=12x{y}^{2} = 12x and the hyperbola 8x2−y2=88{x}^{2} - {y}^{2} = 8. If SS and S′{S}^{'} denote the foci of the hyperbola where SS lies on the positive xx-axis then PP divides SS′S{S}^{'} in a ratio:Let P be the point of intersection of the common tangents to the parabola y ^ 2 = 12x and the hyperbola 8 x ^ 2 - y ^ 2

Options

  1. A5:45: 4
  2. B2:12: 1
  3. C13:1113: 11
  4. D14:1314: 13

Correct answer

A. 5:45: 4

Step-by-step solution

Let mm is slope of common tangent and an equation of tangent to hyperbola x21−y28=1\dfrac{{x}^{2}}{1} - \dfrac{{y}^{2}}{8} = 1 is

y=mx±1⋅m2−8...(1)y = mx \pm \sqrt{1 ⋅ {m}^{2} - 8} . . . \left(1\right)

equation of tangent to parabola y2=12x{y}^{2} = 12x is

y=mx+3m...(2)y = mx + \dfrac{3}{m} . . . \left(2\right)

∵(1) and (2)∵ \left(1\right) \text{ and } \left(2\right) is same

∴±m2−8=3m∴ \pm \sqrt{{m}^{2} - 8} = \dfrac{3}{m}

⇒m4−8m2−9=0⇒m2=−1⇒ {m}^{4} - 8{m}^{2} - 9 = 0 ⇒ {m}^{2} = - 1 (Reject)

⇒m4−8m2−9=0⇒m2=9⇒m=±3⇒ {m}^{4} - 8{m}^{2} - 9 = 0 ⇒ {m}^{2} = 9 ⇒ m = \pm 3

∵∵ equation of common tangents is y=3x+1 and y=−3x−1y = 3x + 1 \text{ and } y = - 3x - 1

∴∴ point of intersection of common tangents is $R(−13,0)R\left(- \dfrac{1}{3}, 0\right) & Foci of hyperbolas are \left(3,0\right) \text{ and } \left(- 3,0\right)</p><p><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeemain/05222085−c988−48e0−ae09−0ff8c8aa63dc−image4.jpeg"style="width:300px;height:116px;"/></p><p></p><p><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/05222085-c988-48e0-ae09-0ff8c8aa63dc-image4.jpeg" style="width: 300px; height: 116px;" /></p><p>⇒ \dfrac{- 3\lambda + 3}{\lambda + 1} = - \dfrac{1}{3} ⇒ \lambda = \dfrac{5}{4}</p><p>Hence,therequiredratiois</p><p>Hence, the required ratio is5: 4$.

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