JEE Main201815 Apr 2018Evening ShiftMathematicsIndefinite IntegrationActual

2 x+5 7-6 x-x^2 d x=A 7-6 x-x^2 +B ⁻¹ ( x+3 4 )+C (where C is a constant of integration), then the ordered pair (A, B) is equal to

Options

A(-2,-1)
B(2,-1)
C(-2,1)
D(2,1)

Correct answer

A. (-2,-1)

Step-by-step solution

7-6 x-x^2=16-(x+3)^2 and d d x (7-6 x-x^2 )=-2 x-6 So, 2 x+5 7-6 x-x^2 d x= 2 x+6 7-6 x-x^2 d x - 1 16-(x+3)^2 d x =-2 7-6 x-x^2 - ⁻¹ ( x+3 4 )+C Therefore, A=-2, & B=-1 .

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