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JEE Main 20178 AprilOnline
Exam
JEE Main
Year
2017
Date
8 April
Mode
Online
Subject
Mathematics
Chapter
Indefinite Integration

JEE Main 2017 · 8 April · Online · Mathematics · Indefinite Integration

The integral ∫ 1 + 2 x( cosecx + x ) dx, (0 < x < (π)/(2)) is equal...

The integral ∫ \sqrt{1 + 2\cot x\left(\text{ cosecx } +\text{ \cot x }\right)}dx, (0<x<π2)\left(0 < x < \dfrac{\pi}{2}\right)is equal to

Options

  1. A2log⁡∣sin⁡x2∣+c2\log \left|\sin\dfrac{x}{2}\right| + c
  2. B4log⁡∣sin⁡x2∣+c4\log \left|\sin\dfrac{x}{2}\right| + c
  3. C4log⁡∣cos⁡x2∣+c4\log \left|\cos\dfrac{x}{2}\right| + c
  4. D2log⁡∣cos⁡x2∣+c2\log \left|\cos\dfrac{x}{2}\right| + c

Correct answer

A. 2log⁡∣sin⁡x2∣+c2\log \left|\sin\dfrac{x}{2}\right| + c

Step-by-step solution

Let I=∫1+2cot⁡x(cosecx+cot⁡x)dxI = ∫ \sqrt{1 + 2\cot x\left(cosecx + \cot x\right)}dx

⇒I=∫(2cot⁡xcos⁡ecx+cosec2x+cot⁡2x)dx⇒ I = ∫ \left(\sqrt{2\cot x \cos ecx + {cosec}^{2}x + \cot^{2}x}\right)dx

⇒I=∫(cosecx+cot⁡x)2dx⇒ I = ∫ \sqrt{{\left(cosecx + \cot x\right)}^{2}}dx

⇒I=∫∣cosecx+cot⁡x∣dx⇒ I = ∫ \left|cosecx + \cot x\right|dx

⇒I=∫(cosecx+cot⁡x)dx⇒ I = ∫ \left(cosecx + \cot x\right)dx

⇒I=log⁡∣tan⁡x2∣+log⁡∣sin⁡x∣+c⇒ I = \log \left|\tan\dfrac{x}{2}\right| + \log \left|\sin x\right| + c, where cc is the constant of integration.
⇒I=log⁡(sinx2cosx2⋅2sinx2cosx2)+c⇒ I = \log \left(\dfrac{sin\dfrac{x}{2}}{cos\dfrac{x}{2}} \cdot 2sin\dfrac{x}{2}cos\dfrac{x}{2}\right) + c
⇒I=2log⁡∣sin⁡x2∣+c⇒ I = 2\log \left|\sin\dfrac{x}{2}\right| + c

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