AP EAMCET202318 May 2023Evening ShiftChemistryElectrochemistryActual
The minimum voltage (in V ) required to bring about the electrolysis of 1 M copper (II) sulphate solution at 298 ~K is (Given E _ Cu ²⁺ / Cu ^ =0.34 ~V and E _ H ₂ O / H ⁺ ^ =-1.23 ~V )
Options
- A+1.57
- B+0.89
- C-0.89
- D-1.57
Correct answer
B. +0.89
Step-by-step solution
Oxidation : (anode) 2 H ₂ O ( I ) O ₂( ~g )+4 H ⁺ (aq.) ; E ^ =+1.23 ~V Reduction : (cathode) aligned & Cu ²⁺( aq .)+2 e ⁻ Cu ( s ) ; E ^ =+0.34 ~V & E _ cell ^ = E _ cathode ^ - E _ anode ^ =(0.34)-(+1.23)=-0.89 ~V . aligned Thus, a potential of minimum of +0.89 ~V would be required to carry out the given reaction.