The number of Faradays required to completely deposit magnesium from 1 ~L of 0.1 M MgCl ₂ aq. solution is

Step-by-step solution

aligned & MgCl ₂ Mg ²⁺+2 Cl ⁻ & Mg ²⁺+2 e ⁻ Mg (s) aligned 2 moles of e ⁻ are required to deposit 1 mole of Mg ( s ) . aligned & 1 mole of e ⁻=1 ~F & 2 moles of e ⁻=2 ~F & n ( MgCl ₂ )=0.1 M 1 ~L =0.1 ~mol . & n ( Mg ²⁺ )=0.1 ~mol . aligned Therefore, the number of moles of electrons/faradays required to deposit 0.1 ~mol of Mg will be 2 0.1= 0 . 2 m o l .