The conductivity of a solution containing 2.08 ~g of anhydrous barium chloride in 200 ~mL solution is 6 10⁻³ ohm ⁻¹ ~cm ⁻¹ . The molar conductivity of the solution (in . ohm ⁻¹ ~cm ^2 ~mol ⁻¹ ) is x 10^2 . The value of x is (Atomic mass of

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The conductivity of a solution containing 2.08 ~g of anhydrous barium chloride in 200 ~mL solution is 6 10⁻³ ohm ⁻¹ ~cm ⁻¹ . The molar conductivity of the solution (in . ohm ⁻¹ ~cm ^2 ~mol ⁻¹ ) is x 10^2 . The value of x is (Atomic mass of Ba =137, Cl =35.5 )

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Correct answer: A. 1.2

Conductivity (k) =6 10⁻³ ⁻¹ ~cm ⁻¹ V =200 ~mL =0.2 ~L mass =2.08 ~g aligned & C = n V = ( mass molar mass ) V = ( 2.08 208 ) 0.2 & =0.05 M . aligned aligned & _ m = K 1000 c = (6 10⁻³ )(1000) 0.05 & =120=1.20 10^2 aligned Thus, x =1.2

The conductivity of a solution containing 2.08 ~g of anhydrous barium chloride in 200 ~mL solution is 6 10⁻³ ohm ⁻¹ ~cm ⁻¹ . The molar conductivity of the solution (in . ohm ⁻¹ ~cm ^2 ~mol ⁻¹ ) is x 10^2 . The value of x is (Atomic mass of Ba =137, Cl =35.5 )

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