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JEE Main 202622 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
22 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Parabola

JEE Main 2026 · 22 January · Evening Shift · Mathematics · Parabola

Let the locus of the mid-point of the chord through the origin O of...

Let the locus of the mid-point of the chord through the origin O of the parabola y2=4xy^{2}=4 x be the curve S. Let P be any point on S. Then the locus of the point, which internally divides OP in the ratio 3:13: 1, is :Let the locus of the mid-point of the chord through the origin O of the parabola y^ 2 =4 x be the curve S. Let P be anyLet the locus of the mid-point of the chord through the origin O of the parabola y^ 2 =4 x be the curve S. Let P be any

Options

  1. A2x2=3y2 x^{2}=3 y
  2. B3y2=2x3 y^{2}=2 x
  3. C2y2=3x2 y^{2}=3 x
  4. D3x2=2y3 x^{2}=2 y

Correct answer

C. 2y2=3x2 y^{2}=3 x

Step-by-step solution

y2=4xy^2 = 4x
Locus of mid point of OP
M(h,k)⇒h=t22,k=tM(h, k) \Rightarrow h = \dfrac{t^2}{2}, k = t
⇒k2=2h⇒y2=2x\Rightarrow k^2 = 2h \Rightarrow y^2 = 2x
Let the locus of the mid-point of the chord through the origin O of the parabola y^ 2 =4 x be the curve S. Let P be any
S:y2=2xS: y^2 = 2x
Let the locus of the mid-point of the chord through the origin O of the parabola y^ 2 =4 x be the curve S. Let P be any
R(h,k)R(h, k)
⇒h=3t24,k=3t4\Rightarrow h = \dfrac{3t^2}{4}, k = \dfrac{3t}{4}
t2=8h3,t=4k3t^2 = \dfrac{8h}{3}, t = \dfrac{4k}{3}
⇒16k29=8h3⇒2k2=3h\Rightarrow \dfrac{16k^2}{9} = \dfrac{8h}{3} \Rightarrow 2k^2 = 3h
Locus of R : 2y2=3x2y^2 = 3x
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