JEE Main202330 Jan 2023Evening ShiftMathematicsParabolaActual
Let A be a point on the x -axis. Common tangents are drawn from A to the curves x 2 + y 2 = 8 and y 2 = 16 x . If one of these tangents touches the two curves at Q and R , then Q R 2 is equal to
Options
- A64
- B76
- C81
- D72
Correct answer
D. 72
Step-by-step solution
Let a tangent on parabola y 2 = 16 x be, y = m x + 4   m It is also common to x 2 + y 2 = 8 If   4 m 2 = 8 1 + m 2 ⇒ 16 m 2 = 8 ( 1 + m 2 ) ⇒ m 4 + m 2 - 2 = 0 ⇒ ( m 2 + 2 ) ( m 2 - 1 ) = 0 ⇒ m = ± 1 Taking one of the tangents y = x + 4 ⇒ x - y + 4 = 0 Tangent to x 2 + y 2 = 8 is x x 1 + y y 1 - 8 = 0 ∴ x 1 1 = y 1 1 = - 8 4 ⇒ Q ( - 2 , 2 ) Tangent to y 2 = 16 x is y y 1 = 8 ( x + x 1 ) ⇒ 8 x - y y 1 + 8 x 1 = 0 ∴ 8 1 = - y 1 - 1 = 8 x 1 4 ⇒