In the electrolysis of a CuSO 4 solution, how many grams of Cu are plated out on the cathode, in the time that is required to liberate 5 . 6 L of O 2 ( g ) , measured at 1 atm and 273 K , at the anode?

Step-by-step solution

The mole of oxygen = Given   volume Molar   volume = 5 . 6 22 . 4 = 0 . 25   mol Equivalent of oxygen = n - factor × mole n - factor = 4 Equivalent of oxygen= 4 × 0 . 25 = 1 So, Equivalent of oxygen = Equivalent of copper Equivalent mass of copper= Molar   mass n - factor = 63 . 5 2 Equivalent of coper = mass   of   copper Equivalent   mass = mass   of   copper 63 . 5 2 Equivalent of oxygen = Equivalent of copper 1 = mass   of   copper 63 . 5 2 mass &