AP EAMCET202119 Aug 2021Evening ShiftChemistryElectrochemistryActual
At 291 K , saturated solution of BaSO 4 was found to have a specific conductivity of 3 . 648 × 10 - 6 ohm - 1 cm - 1 and that of water being used is 1 . 25 × 10 - 6 ohm - 1 cm - 1 . If the ionic conductance's of Ba 2 + and SO 4 2 - are 110 and 136 . 6 ohm - 1 cm 2 mol - 1 respectively, the solubility of BaSO 4 at 291 K will be [Atomic masses of Ba - 137 , S - 32 , 0 - 16
Options
- A1 .435 × 10 − 3 gL − 1
- B2 .266 × 10 − 3 gL − 1
- C2 .843 × 10 − 3 gL − 1
- D1 .768 × 10 − 3 gL − 1
Correct answer
B. 2 .266 × 10 − 3 gL − 1
Step-by-step solution
According to Kohlrausch's law λ ° m BaSO 4   =   λ ° m Ba 2 + + λ ° m SO 4 2 - λ ° m BaSO 4     =   110 + 136 . 6 λ ° m BaSO 4     =     246 . 6   ohm - 1 cm - 1 Now, the solubility product of BaSO 4 can be determined by: K BaSO 4   =   K BaSO 4 solution - K water K BaSO 4   =   3 . 648 × 10 - 6 - 1 . 25 × 10 - 6 K BaSO 4   =   2 . 398 × 10 - 6   S   cm - 1 F