AP EAMCET202119 Aug 2021Morning ShiftChemistryElectrochemistryActual
The molar conductivities λ m 0 at infinite dilution of KBr , HBr and KNH 2 are 120 . 5 , 420 . 6 and 90 . 48 S cm 2 mol - 1 respectively. Find the value of λ m 0 for NH 3 .
Options
- A511 .0 S   cm 2 mol − 1
- B390.5   S   cm 2 mol − 1
- C256.2   S   cm 2 mol − 1
- D240.9   S   cm 2 mol − 1
Correct answer
B. 390.5   S   cm 2 mol − 1
Step-by-step solution
For KBr :- λ KBr =   λ K +   +   λ Br - 120 . 5 = λ K +   +   λ Br - For HBr :- λ HBr =   λ H +   +   λ Br - 420 . 6 =   λ H +   +   λ Br - For KNH 2 :- λ KNH 2 =   λ K +   +   λ NH 2 - 90 . 48 = λ K +   +     λ NH 2 - For, NaNO 3 : - λ NH 3 =   λ H +   +   λ NH 2 - = λ KNH 2 + λ HBr - λ KBr = 90 . 48 + 420 . 6 -