The electrode potential for aligned & M²⁺(a q)+e⁻ M⁺(a q) & M⁺(a q)+e⁻ M(s) aligned are +0.15 ~V and +0.50 ~V respectively. The value of E^ _ M²⁺ / M will be

Step-by-step solution

Given, aligned & M²⁺(a q)+e⁻ M⁺(a q), E₁^ =+0.15 ~V & M⁺(a q)+e⁻ M(s), E₂^ =0.5 ~V aligned Free energy, i.e. [ G^ ]=-n F E^ where, n= number of electron involved E^ = standard electrode potential. F= Faraday's constant To find E₃^ for E_ (M²⁺ / M ) ^ Thus, array lr - G₁^ =n E₁^ =E₁^ & ( n=1) - G₂^ =n E₂^ =E_ ₂ ₂ & ( n=1) - G₃^ =n E₃=2 E₃^ & ( n=2) [For reaction : M²⁺(a q)+2 e⁻ & M(s) ] array Therefore, aligned - G₃^ & =(-) G₁^ +(-) G₂^ -2 E₃^ & =- (n E₁^ +n E₂^ ) 2 E₃^ & =E₁^ +E₂^ 2 E₃^ & =0.15+0.5 2 E₃^ & =0.65 ~V