The emf of the following cell Mg | Mg ⁺²(0.01 M ) | | Sn ⁺²(0.1 M ) | Sn at 298 ~K in ' V ' is ( . Given, .E_ Mg ⁺² Mg ^ =-2.34 ~V , E_ Sn ⁺² Sn ^ =-0.14 ~V )

Step-by-step solution

At anode, Mg Mg ²⁺+2 e⁻ At cathode, Sn ²⁺+2 e⁻ Sn From Nernst equation, aligned E_ cell & =E_ cell ^ - 0.0591 n Mg ⁺² Sn ⁺² E_ cell & =-0.14-(-2.34)- 0.0591 2 10⁻¹ ( n=2 e⁻ ) & =2.2+ 0.0591 2 & =2.2+0.0295 2.23 aligned