For the oxidation of 0.2 M FeSO ₄ solution 0.965 amperes current is passed through it for 1 hour. The volume of the solution that is oxidised in mL is

Step-by-step solution

The equation is Fe ²⁺+2 e ⁻ Fe 1 mole is deposited by 2 96500^ C =193000^ C The charged supplied =0.965 60 60 =3474 C ( Q=i t) Number of moles deposited by this charge aligned & = 3474 193000 =0.018 ~mol & Molarity = Number of moles 1000 Volume in mL & Volume ( in mL )= Number of moles 1000 M( molarity ) & = 0.018 1000 0.2 =90 ~mL & aligned