The emf (in V) of a Daniell cell containing 0.1 MZnSO ₄ and 0.01 M CuSO ₄ solutions at their respective electrodes is (E_ Cu ²⁺ / Cu ^ =+0.34 ~V ; E_ Zn ²⁺ / Zn ^ =-0.76 ~V )

Step-by-step solution

aligned E_ cell ^ & =E_ Cu ²⁺ / Cu ⁻ ^ -E_ Zn ²⁺ / Zn ^ & =+0.34-(-0.76) V & =1.1 ~V aligned Further E_ cell =E_ cell ^ - 0.059 n [products] [reactants] For the reaction, CuSO ₄+ Zn ZnSO ₄+ Cu Cu ²⁺+ Zn Zn ²⁺+ Cu aligned E_ cell & =E_ cell ^ - 0.059 2 [ Zn ²⁺ ] [ Cu ²⁺ ] & =1.1- 0.059 2 0.1 0.01 & =1.1- 0.059 2 10 & =1.1-0.0295 1 [ 10=1] & =1.07 ~V aligned