JEE Main2004MathematicsQuadratic EquationActual
Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equation
Options
- Ax^2+18 x+16=0
- Bx^2-18 x-16=0
- Cx^2+18 x-16=0
- Dx^2-18 x+16=0
Correct answer
D. x^2-18 x+16=0
Step-by-step solution
Let numbers be a, b a+b=18, a b =4 a b=16, a and b are roots of the equation x^2-18 x+16=0