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JEE Main 2004

Exam: JEE Main
Year: 2004
Subject: Mathematics
Chapter: Quadratic Equation

JEE Main 2004 · Mathematics · Quadratic Equation

Let two numbers have arithmetic mean 9 and geometric mean 4. Then...

Let two numbers have arithmetic mean 9 and geometric mean 4. Then these numbers are the roots of the quadratic equation

Options

A $x^2+18 x+16=0$
B $x^2-18 x-16=0$
C $x^2+18 x-16=0$
D $x^2-18 x+16=0$

Correct answer

D. $x^2-18 x+16=0$

Step-by-step solution

Let numbers be

a, b \Rightarrow a+b=18, \sqrt{a b}=4 \quad \Rightarrow a b=16, a

and

b

are roots of the equation

\Rightarrow \quad x^2-18 x+16=0

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