JEE Main2004MathematicsQuadratic EquationActual
If (1-p) is a root of quadratic equation x^2+p x+(1-p)=0 , then its roots are
Options
- A0,1
- B-1,2
- C0,-1
- D-1,1
Correct answer
C. 0,-1
Step-by-step solution
(3) aligned & (1-p)^2+p(1-p)+(1-p)=0 ( since (1-p) is a root of the equation x^2+p x+(1-p)=0 ) & (1-p)(1-p+p+1)=0 & 2(1-p)=0 (1-p)=0 p=1 & sum of root is + =-p and product =1-p=0 (where =1-p=0) & +0=-1 =-1 Roots are 0,-1 aligned