JEE Main2004MathematicsQuadratic EquationActual
If one root of the equation x^2+p x+12=0 is 4 , while the equation x^2+p x+q=0 has equal roots, then the value of ' q ' is
Options
- A49 4
- B4
- C3
- D12
Correct answer
A. 49 4
Step-by-step solution
Since 4 is one of the root of x^2+p x+12=0 16+4 p+12=0 p=-7 and equation x^2+p x+q=0 has equal roots D=49-4 q=0 q= 49 4