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Let a₁, a₂, , a₂₀₂₄ be an Arithmetic Progression such that a₁+ (a₅+a₁₀+a₁₅+ +a₂₀₂₀ )+a₂₀₂₄=2233 . Then a₁+a₂+a₃+ +a₂₀₂₄ is equal to _______

Correct answer

0

Step-by-step solution

As a₁+a₅+a₁₀+ +a₂₀₂₀+a₂₀₂₄=2233 ...(1) We know in arithmetic progression. Sum of terms equidistant from ends is equal from (1) a₁+a₂₀₂₄=a₅+a₂₀₂₀=a₁₀+a₂₀₁₅= _ 203 pairs aligned & 203 (a₁+a₂₀₂₄ )=2233 & a₁+a₂₀₂₄=11 aligned Now aligned _ i=1 ²⁰²⁴ a_i & =S₂₀₂₄= 2024 2 [a₁+a₂₀₂₄ ] & =1012(11) & =11132 aligned

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