JEE Main 2025 23 January Morning Shift
Exam JEE Main
Year 2025
Date 23 January
Shift Morning Shift
Subject Mathematics
Chapter Sequences and Series
JEE Main 2025 · 23 January · Morning Shift · Mathematics · Sequences and Series
If the first term of an A.P. is 3 and the sum of its first four...
If the first term of an A.P. is 3 and the sum of its first four terms is equal to one-fifth of the sum of the next four terms, then the sum of the first 20 terms is equal to
Options A − 1080 -1080 − 1080 B − 1020 -1020 − 1020 C − 1200 -1200 − 1200 D − 120 -120 − 120
Correct answer A. − 1080 -1080 − 1080
Step-by-step solution
a = 3 S 4 = 1 5 ( S 8 − S 4 ) ⇒ 5 S 4 = S 8 − S 4 ⇒ 6 S 4 = S 8 ⇒ 6 ⋅ 4 2 [ 2 × 3 + ( 4 − 1 ) × d ] = 8 2 [ 2 × 3 + ( 8 − 1 ) d ] ⇒ 12 ( 6 + 3 d ) = 4 ( 6 + 7 d ) ⇒ 18 + 9 d = 6 + 7 d ⇒ d = − 6 S 20 = 20 2 [ 2 × 3 + ( 20 − 1 ) ( − 6 ) ] = 10 [ 6 − 114 ] = − 1080 \begin{aligned} & \mathrm{a}=3 \\ & \mathrm{~S}_4=\frac{1}{5}\left(\mathrm{~S}_8-\mathrm{S}_4\right) \\ & \Rightarrow 5 \mathrm{~S}_4=\mathrm{S}_8-\mathrm{S}_4 \\ & \Rightarrow 6 \mathrm{~S}_4=\mathrm{S}_8 \\ & \Rightarrow 6 \cdot \frac{4}{2}[2 \times 3+(4-1) \times \mathrm{d}] \\ & =\frac{8}{2}[2 \times 3+(8-1) \mathrm{d}] \\ & \Rightarrow 12(6+3 \mathrm{~d})=4(6+7 \mathrm{~d}) \\ & \Rightarrow 18+9 \mathrm{~d}=6+7 \mathrm{~d} \\ & \Rightarrow \mathrm{~d}=-6 \\ & \mathrm{~S}_{20}=\frac{20}{2}[2 \times 3+(20-1)(-6)] \\ & =10[6-114] \\ & =-1080\end{aligned} a = 3 S 4 = 5 1 ( S 8 − S 4 ) ⇒ 5 S 4 = S 8 − S 4 ⇒ 6 S 4 = S 8 ⇒ 6 ⋅ 2 4 [ 2 × 3 + ( 4 − 1 ) × d ] = 2 8 [ 2 × 3 + ( 8 − 1 ) d ] ⇒ 12 ( 6 + 3 d ) = 4 ( 6 + 7 d ) ⇒ 18 + 9 d = 6 + 7 d ⇒ d = − 6 S 20 = 2 20 [ 2 × 3 + ( 20 − 1 ) ( − 6 )] = 10 [ 6 − 114 ] = − 1080
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