JEE Main202310 Apr 2023Evening ShiftMathematicsSequences and SeriesActual
If S n = 4 + 11 + 21 + 34 + 50 + … to n terms, then 1 60 S 29 - S 9 is equal to
Options
- A223
- B226
- C220
- D227
Correct answer
A. 223
Step-by-step solution
Given, S n = 4 + 11 + 21 + 34 + . . . . . . . . . . . . + T n S n =                 4 + 11 + 21 + 34 . . . . . . + T n - 1 + T n Subtracting above equations, we get 0 = 4 + 7 + 10 + 13 + . . . . - T n ⇒ T n = 4 + 7 + 10 + 13 + . . . The above series is in AP. ⇒ T n = n 2 2 × 4 + n - 1 3 ⇒ T n = n 2 3 n + 5 So, S n = ∑ 3 n 2 + 5 n 2 ⇒ S n = 1 2 3 n ( n + 1 ) ( 2 n + 1 ) 6 + 5 n n + 1 2 ⇒ S n = n n + 1 2 ( 2 n + 1 ) 2 + 5 2 ⇒ S 29