Let the relations R₁ and R₂ on the set X= 1,2,3, , 20 be given by R₁= (x, y): 2 x-3 y=2 and R₂= (x, y):-5 x+4 y=0 . If M and N be the minimum number of elements required to be added in R₁ and R₂ , respectively, in order to make the relation

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Let the relations R₁ and R₂ on the set X= 1,2,3, , 20 be given by R₁= (x, y): 2 x-3 y=2 and R₂= (x, y):-5 x+4 y=0 . If M and N be the minimum number of elements required to be added in R₁ and R₂ , respectively, in order to make the relations symmetric, then M+N equals

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Correct answer: D. 10

aligned & x = 1,2,3, . .20 & R ₁= ( x , y ): 2 x -3 y =2 & R ₂= ( x , y ):-5 x +4 y =0 aligned aligned & R ₁= (4,2),(7,4),(10,6),(13,8),(16,10),(19,12) & R ₂= (4,5),(8,10),(12,15),(16,20) aligned in R₁ 6 element needed in R₂ 4 element needed So, total 6+4=10 element

Let the relations R₁ and R₂ on the set X= 1,2,3, , 20 be given by R₁= (x, y): 2 x-3 y=2 and R₂= (x, y):-5 x+4 y=0 . If M and N be the minimum number of elements required to be added in R₁ and R₂ , respectively, in order to make the relations symmetric, then M+N equals

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