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JEE Main 20236 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
6 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Sets and Relations

JEE Main 2023 · 6 April · Evening Shift · Mathematics · Sets and Relations

In a group of 100 persons 75 speak English and 40 speak Hindi. Each...

In a group of 100100 persons 7575 speak English and 4040 speak Hindi. Each person speaks at least one of the two languages. If the number of persons who speak only English is α\alpha and the number of persons who speaks only Hindi is β\beta, then the eccentricity of the ellipse 25(β2x2+α2y2)=α2β225\left({\beta}^{2}{x}^{2} + {\alpha}^{2}{y}^{2}\right) = {\alpha}^{2}{\beta}^{2} is

In a group of 100 persons 75 speak English and 40 speak Hindi. Each person speaks at least one of the two languages. If

Options

  1. A11912\dfrac{\sqrt{119}}{12}
  2. B11712\dfrac{\sqrt{117}}{12}
  3. C31512\dfrac{3\sqrt{15}}{12}
  4. D12912\dfrac{\sqrt{129}}{12}

Correct answer

A. 11912\dfrac{\sqrt{119}}{12}

Step-by-step solution

Given,

In a group of 100100 persons 7575 speak English and 4040 speak Hindi,

And each person speaks at least one of the two languages,

And the number of persons who speak only English is α\alpha and the number of persons who speaks only Hindi is β\beta,

In a group of 100 persons 75 speak English and 40 speak Hindi. Each person speaks at least one of the two languages. If

Now from above diagram we can see that,

β=100−75=25\beta = 100 - 75 = 25

So, α=75−(40−25)=60\alpha = 75 - \left(40 - 25\right) = 60

Hence, number of people who speak English only is α=60\alpha = 60 and Hindi is β=25\beta = 25,

Now putting the value in given equation of ellipse we get,

25[x2602+y2252]=125\left[\dfrac{{x}^{2}}{{60}^{2}} + \dfrac{{y}^{2}}{{25}^{2}}\right] = 1

⇒x236×4+y225=1⇒ \dfrac{{x}^{2}}{36 \times 4} + \dfrac{{y}^{2}}{25} = 1

Now comparing with x2a2+y2b2=1\dfrac{{x}^{2}}{{a}^{2}} + \dfrac{{y}^{2}}{{b}^{2}} = 1 we get, a=12 and b=5a = 12 \text{ and } b = 5

Now we know that,

Eccentricity of ellipse is given by e=1−b2a2e = \sqrt{1 - \dfrac{{b}^{2}}{{a}^{2}}}

⇒e=1−2536×4=11912⇒ e = \sqrt{1 - \dfrac{25}{36 \times 4}} = \dfrac{\sqrt{119}}{12}

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