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JEE Main 202127 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
27 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Sets and Relations

JEE Main 2021 · 27 August · Evening Shift · Mathematics · Sets and Relations

Let Z be the set of all integers, A = \ ( x, y ) ∈ Z × Z: ( x - 2 )...

Let ZZ be the set of all integers,
A={(x,y)∈Z×Z:(x−2)2+y2≤4}A = \left\{( x, y ) \in Z \times Z: ( x - 2{)}^{2} + {y}^{2} \le 4\right\}

B={(x,y)∈Z×Z:x2+y2≤4}andB = \left\{( x, y ) \in Z \times Z: {x}^{2} + {y}^{2} \le 4\right\}\text{and}

C={(x,y)∈Z×Z:(x−2)2+(y−2)2≤4}C = \left\{( x, y ) \in Z \times Z: ( x - 2{)}^{2} + ( y - 2{)}^{2} \le 4\right\}
If the total number of relations from A∩BA \cap B to A∩CA \cap C is 2p{2}^{p}, then the value of pp is:

Let Z be the set of all integers, A = \ ( x, y ) ∈ Z × Z: ( x - 2 ) ^ 2 + y ^ 2 ≤ 4\ B = \ ( x, y ) ∈ Z × Z: x ^ 2 + y

Options

  1. A2525
  2. B99
  3. C1616
  4. D4949

Correct answer

A. 2525

Step-by-step solution

A={(x,y)∈Z×Z;(x−2)2+y2≤4}A = \left\{( x, y ) \in Z \times Z; ( x - 2{)}^{2} + {y}^{2} \le 4\right\}

B={(x,y)≤Z×Z;x2+y2≤4}B = \left\{( x, y ) \le Z \times Z; {x}^{2} + {y}^{2} \le 4\right\}

C={(x,y)∈Z×Z;(x−2)2+(y−2)2≤4}C = \left\{( x, y ) \in Z \times Z; ( x - 2{)}^{2} + ( y - 2{)}^{2} \le 4\right\}

Let Z be the set of all integers, A = \ ( x, y ) ∈ Z × Z: ( x - 2 ) ^ 2 + y ^ 2 ≤ 4\ B = \ ( x, y ) ∈ Z × Z: x ^ 2 + y

Here, we can see from the above diagram A∩B=(0,0),(1,0),(2,0),(1,1),(1,−1)⇒n(A∩B)=5A \cap B = { ( 0, 0 ) , ( 1, 0 ) , ( 2, 0 ) , ( 1, 1 ) , ( 1, - 1 ) } ⇒ n ( A \cap B ) = 5

Similarly n(A∩C)=5n ( A \cap C ) = 5

Relation from A∩BA \cap B to A∩C=25×5=2pA \cap C = {2}^{5 \times 5} = {2}^{p}

⇒p=25⇒ p = 25

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