A survey shows that 73 % of the persons working in an office like...

$n\left(C\right) = 73, n\left(T\right) = 65, n\left(C \cap T\right) = x$,

Considering that value of $n\left(C \cup T\right)$ cannot exceed $100$ in terms of percentage, we get

$n\left(C \cup T\right) \le 100$

$⇒ n\left(C\right) + n\left(T\right) - n\left(C \cap T\right) \le 100$

$⇒ x \ge 38$

Therefore, $x \ne 36$.

$n\left(C \cap T\right) \le min\left(n\left(C\right), n\left(T\right)\right) ⇒ x \le 65$

$⇒ 38 \le x \le 65$

Hence $x$ may assume values $63, 54, 38$.